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15x^2-102x+135=0
a = 15; b = -102; c = +135;
Δ = b2-4ac
Δ = -1022-4·15·135
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-48}{2*15}=\frac{54}{30} =1+4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+48}{2*15}=\frac{150}{30} =5 $
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